a^2-13a+22=(a-2)(a-)

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Solution for a^2-13a+22=(a-2)(a-) equation: 



a^2-13a+22=(a-2)(a-)

We move all terms to the left:

a^2-13a+22-((a-2)(a-))=0

We add all the numbers together, and all the variables

a^2-13a-((a-2)(+a))+22=0

We multiply parentheses ..

a^2-((+a^2-2a))-13a+22=0



We calculate terms in parentheses: -((+a^2-2a)), so:

(+a^2-2a)

We get rid of parentheses

a^2-2a

Back to the equation:

-(a^2-2a)



We add all the numbers together, and all the variables

a^2-13a-(a^2-2a)+22=0

We get rid of parentheses

a^2-a^2-13a+2a+22=0

We add all the numbers together, and all the variables

-11a+22=0

We move all terms containing a to the left, all other terms to the right

-11a=-22

a=-22/-11

a=+2

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